NEON_TUBE_FLASHER

Published:2009/6/30 2:57:00 Author:May | From:SeekIC

The voltage required to ignite the neon tube is obtained by using an ordinary filament transformer (240-6.3 V) in reverse. Battery drain is quite low, around 1 to 2 milliamps for a nine volt battery. The pulses from Q1, uni-junction transistor, operated as a relaxation oscillator and are applied to Q2 which in turn drives Q3 into saturation. The sharp rise in current through the 6.3 V winding of the trans-former as Q3 goes into saturation induces a high voltage in the secondary winding causing the neon to flash. The diode Dl protects the transistor from high voltage spikes generated when switching currents in the transformer.



Reprinted Url Of This Article:
http://www.seekic.com/circuit_diagram/LED_and_Light_Circuit/NEON_TUBE_FLASHER.html

Print this Page | Comments | Reading(3)